HRID561579

反应详情

EQUATION

反应方程式

HRID 561579 的结构方程式

PROCEDURE

实验过程

The title compound was prepared starting from 500 mg (2.82 mmol) of the compound from Example 8 and 615 mg (3.10 mmol) of the compound from Example 78A in analogy to the synthesis of the compound from Example 95. 227 mg (94% purity, 21% of theory) of the target compound were obtained.

WORKUP

后处理

  1. custom227 mg (94% purity, 21% of theory) of the target compound were obtained