HRID561585

反应详情

EQUATION

反应方程式

HRID 561585 的结构方程式

PROCEDURE

实验过程

The title compound was prepared starting from 380 mg (2.14 mmol) of the compound from Example 8 and 591 mg (2.36 mmol) of the compound from Example 83A in analogy to the synthesis of the compound from Example 101. 307 mg (35% of theory) of the target compound were obtained.

WORKUP

后处理

  1. custom307 mg (35% of theory) of the target compound were obtained