HRID561588

反应详情

EQUATION

反应方程式

HRID 561588 的结构方程式

PROCEDURE

实验过程

The title compound was prepared starting from 500 mg (2.56 mmol) of the compound from Example 9 and 652 mg (2.56 mmol) of the compound from Example 85A in analogy to the synthesis of the compound from Example 101. 197 mg (18% of theory) of the target compound were obtained.

WORKUP

后处理

  1. custom197 mg (18% of theory) of the target compound were obtained