HRID561644

反应详情

EQUATION

反应方程式

HRID 561644 的结构方程式

PROCEDURE

实验过程

The title compound was prepared starting from 450 mg (2.54 mmol) of the compound from Example 8A and 574 mg (2.54 mmol) of the compound from Example 172A in analogy to the synthesis of the compound from Example 193. 80 mg (8% of theory) of the target compound were obtained.

WORKUP

后处理

  1. custom80 mg (8% of theory) of the target compound were obtained