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HRID561648

反应详情

EQUATION

反应方程式

HRID 561648 的结构方程式

REACTANTS

反应物

2
结构：CC(c1ccc(Cl)cc1)(c1c[nH]c2c(CS(C)(=O)=O)cccc12)C1CC1
HCID58392388

未命名化合物

结构：CSCc1cccc2c(C(C)(c3ccc4sccc4c3)C3CC3)c[nH]c12
HCID58392458

未命名化合物

PRODUCTS

生成物

1
结构：CC(c1ccc2sccc2c1)(c1c[nH]c2c(CS(C)(=O)=O)cccc12)C1CC1
HCID58392189

未命名化合物

PROCEDURE

实验过程

The title compound was prepared starting from 237 mg (0.63 mmol) of the compound from Example 187 in analogy to the synthesis of the compound from Example 209. 144 mg (56% of theory) of the target compound were obtained.

WORKUP

后处理

  1. custom144 mg (56% of theory) of the target compound were obtained