HRID561649

反应详情

EQUATION

反应方程式

HRID 561649 的结构方程式

PROCEDURE

实验过程

The title compound was prepared starting from 94 mg (0.25 mmol) of the compound from Example 188 in analogy to the synthesis of the compound from Example 209. 56 mg (55% of theory) of the target compound were obtained.

WORKUP

后处理

  1. custom56 mg (55% of theory) of the target compound were obtained