HRID561650

反应详情

EQUATION

反应方程式

HRID 561650 的结构方程式

PROCEDURE

实验过程

The title compound was prepared starting from 214 mg (0.59 mmol) of the compound from Example 189 in analogy to the synthesis of the compound from Example 209. 162 mg (69% of theory) of the target compound were obtained.

WORKUP

后处理

  1. custom162 mg (69% of theory) of the target compound were obtained