HRID561660

反应详情

EQUATION

反应方程式

HRID 561660 的结构方程式

PROCEDURE

实验过程

The title compound was prepared starting from 300 mg (1.69 mmol) of the compound from Example 8A and 312 mg (1.69 mmol) of the compound from Example 154A in analogy to the synthesis of the compound from Example 227. 170 mg (29% of theory) of the target compound were obtained.

WORKUP

后处理

  1. custom170 mg (29% of theory) of the target compound were obtained