HRID561661

反应详情

EQUATION

反应方程式

HRID 561661 的结构方程式

PROCEDURE

实验过程

The title compound was prepared starting from 500 mg (2.82 mmol) of the compound from Example 8A and 566 mg (2.82 mmol) of the compound from Example 155A in analogy to the synthesis of the compound from Example 227. 394 mg (39% of theory) of the target compound were obtained.

WORKUP

后处理

  1. custom394 mg (39% of theory) of the target compound were obtained