HRID561678

反应详情

EQUATION

反应方程式

HRID 561678 的结构方程式

PROCEDURE

实验过程

The title compound was prepared starting from 238 mg (0.66 mmol) of the compound from Example 234 in analogy to the synthesis of the compound from Example 209. 144 mg (55% of theory) of the target compound were obtained.

WORKUP

后处理

  1. custom144 mg (55% of theory) of the target compound were obtained