HRID561699

反应详情

EQUATION

反应方程式

HRID 561699 的结构方程式

PROCEDURE

实验过程

The title compound was prepared starting from 750 mg (4.23 mmol) of the compound from Example 8A and 1.05 g (4.23 mmol) of the compound from Example 175A in analogy to the synthesis of the compound from Example 278. 262 mg (15% of theory) of the target compound were obtained.

WORKUP

后处理

  1. custom262 mg (15% of theory) of the target compound were obtained