HRID561702

反应详情

EQUATION

反应方程式

HRID 561702 的结构方程式

PROCEDURE

实验过程

The title compound was prepared starting from 490 mg (2.76 mmol) of the compound from Example 8A and 753 mg (2.76 mmol) of the compound from Example 178A in analogy to the synthesis of the compound from Example 278. 140 mg (12% of theory) of the target compound were obtained.

WORKUP

后处理

  1. custom140 mg (12% of theory) of the target compound were obtained