HRID561704

反应详情

EQUATION

反应方程式

HRID 561704 的结构方程式

PROCEDURE

实验过程

The title compound was prepared starting from 750 mg (4.23 mmol) of the compound from Example 8A and 1.14 g (4.23 mmol) of the compound from Example 180A in analogy to the synthesis of the compound from Example 278. 554 mg (31% of theory) of the target compound were obtained.

WORKUP

后处理

  1. custom554 mg (31% of theory) of the target compound were obtained