HRID561707

反应详情

EQUATION

反应方程式

HRID 561707 的结构方程式

PROCEDURE

实验过程

The title compound was prepared starting from 1.00 g (5.64 mmol) of the compound from Example 8A and 1.52 g (5.64 mmol) of the compound from Example 183A in analogy to the synthesis of the compound from Example 278. 0.95 g (39% of theory) of the target compound were obtained.

WORKUP

后处理

  1. custom0.95 g (39% of theory) of the target compound were obtained