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HRID567437

反应详情

EQUATION

反应方程式

HRID 567437 的结构方程式

REACTANTS

反应物

4
结构：CN[C@H]1CC[C@@]2(O)[C@H]3Cc4ccc(O)c5c4[C@@]2(CCN3CC2CC2)[C@H]1O5
HCID15908858

(5α,6α)-17-(Cyclopropylmethyl)-4,5-epoxy-6-(methylamino)morphinan-3,14-diol

C21H28N2O3

结构：O=C(Cl)C=Cc1cccc(OC(F)(F)F)c1
HCID53895214

未命名化合物

结构：CN[C@H]1C[C@@H]2Oc3c(O)ccc4c3[C@@]23CCN(CC2CC2)[C@H](C4)[C@]3(O)C1
HCID70220768

未命名化合物

结构：CN[C@@H]1C[C@@H]2Oc3c(O)ccc4c3[C@@]23CCN(CC2CC2)[C@H](C4)[C@]3(O)C1
HCID70221550

未命名化合物

PRODUCTS

生成物

2
结构：CN(C(=O)C=Cc1cccc(OC(F)(F)F)c1)[C@@H]1C[C@@H]2Oc3c(O)ccc4c3[C@@]23CCN(CC2CC2)[C@H](C4)[C@]3(O)C1.Cl
HCID86756298

未命名化合物

收率 68%
结构：CN(C(=O)C=Cc1cccc(OC(F)(F)F)c1)[C@H]1C[C@@H]2Oc3c(O)ccc4c3[C@@]23CCN(CC2CC2)[C@H](C4)[C@]3(O)C1.Cl
HCID86756300

未命名化合物

收率 71%

PROCEDURE

实验过程

The procedure of Example 11 was repeated, except that 17-cyclopropylmethyl-4,5α-epoxy-3,14β-dihydroxy-7α-methylaminomorphinan and 17-cyclopropylmethyl-4,5α-epoxy-3,14β-dihydroxy-7β-methylaminomorphinan were used instead of 17-cyclopropylmethyl-4,5α-epoxy-3,14β-dihydroxy-6α-methylaminomorphinan 4 and 3-trifluoromethoxycinnamoyl chloride was used instead of 3,4-dichlorophenylacetyl chloride, thereby preparing 17-cyclopropylmethyl-4,5α-epoxy-3,14β-dihydroxy-7α-(N-methyl-3-trifluoromethoxycinnamamido)morphinan hydrochloride 243 (yield: 68%) and 17-cyclopropylmethyl-4,5α-epoxy-3,14β-dihydroxy-7β-(N-methyl-3-trifluoromethoxycinnamamido)morphinan hydrochloride 244 (yield: 71%).