HRID574158

反应详情

EQUATION

反应方程式

HRID 574158 的结构方程式

PROCEDURE

实验过程

Analogously to Example 1, 25 mg (72 μmol) of the compound of Example 11A and 29 mg (79 μmol) of the compound of Example 62A were employed. Purification by HPLC [Method 7] gave 32 mg (70% of theory) of the title compound.

WORKUP

后处理

  1. customPurification by HPLC [Method 7]