HRID574300

反应详情

EQUATION

反应方程式

HRID 574300 的结构方程式

PROCEDURE

实验过程

This compound was prepared from 37b (4.8 g, 13.8 mmol) and LiAlH4 (2.0 g, 55.2 mmol) by following Procedure E to give 38b (4.2 g, 91%). 1H NMR (400 MHz, CDCl3) 0.92-0.96 (t, 3H, J=7.6 Hz), 1.41-1.59 (m, 3H), 1.98-2.22 (m, 1H), 2.41-3.1 (m, 19H), 3.81 (s, 3H), 5.2 (bs, 1H), 6.58-6.60 (d, 1H, J=8 Hz), 6.70-6.72 (d, 1H, J=8 Hz), 7.04-7.1 (t, 1H, J=8 Hz).