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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 578788Generated: October 31, 2026

Phenylacetylene → 1-Fluoro-5-methoxy-2-nitro-4-(2-phenylethynyl)benzene

https://huagongshe.com/reaction/578788

Reaction equation

Participants

RoleNameHCIDCharge
ReactantPhenylacetyleneHCID 10821—
ReactantHCID 68996065HCID 68996065—
CatalystCopper(1+) iodide; Copper(I) iodide; Cuprous iodide; Cuprous iodide (CuI)HCID 24350—
CatalystTetrakis(triphenylphosphine)palladiumHCID 11979704—
SolventDiisopropylamineHCID 7912—
SolventEthyl AcetateHCID 8857—
Product1-Fluoro-5-methoxy-2-nitro-4-(2-phenylethynyl)benzeneHCID 68995941101.2%

Reaction Steps

A mixture of 2-bromo-5-fluoro-4-nitroanisole (0.46 g), phenylacetylene (67 mg), tetrakis(triphenylphosphine) -palladium(0) (38 mg) and copper (I) iodide (13 mg) in N,N-diisopropylamine (5 mL) was stirred at room temperature overnight. The reaction mixture was diluted with ethyl acetate. The insoluble material was removed by filtration, and the filtrate was concentrated under reduced pressure. The residue was purified by column chromatography on silica gel (eluent: n-hexane/ethyl acetate=10/1−5/1) to give 5-fluoro-4-nitro-2-phenylethynylanisole (0.18 g). This material was dissolved in ethyl acetate (5 mL). To the solution was added 10% palladium-carbon powder (0.45 g), and the mixture was stirred at room temperature under a hydrogen atmosphere for 3 hours. The insoluble material was removed by filtration, and the filtrate was concentrated under reduced pressure. The residue was purified by column chromatography on silica gel (eluent: n-hexane/ethyl acetate=10/1−4/1) to give the title compound (87 mg).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS09040693B2
Source datasetuspto-grants-2015_05
ORD IDord-412419cdc32249eaa8dc39f5a712a74b
Source noteuspto-grants-2015_05