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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 581453Generated: October 31, 2026

Dichloromethane → [3-(Diphenylphosphanyl)propyl](oxo)diphenyl-lambda~5~-phosphane

https://huagongshe.com/reaction/581453

Reaction equation

Participants

RoleNameHCIDCharge
ReactantDichloromethaneHCID 6344—
Reactant1,2-DibromoethaneHCID 7839—
ReactantSodium HydroxideHCID 14798—
Reactant1,3-Bis(diphenylphosphino)propaneHCID 81219—
Catalystpalladium(II) acetateHCID 167845—
Solvent1,2-DichloroethaneHCID 11—
SolventDiethyl EtherHCID 3283—
SolventPentaneHCID 8003—
Product[3-(Diphenylphosphanyl)propyl](oxo)diphenyl-lambda~5~-phosphaneHCID 3336369—

Reaction Steps

Palladium acetate (10 mg; 4.45×10-2 mmol), dppp (5.00 g; 12.14 mmol), and 1,2-dibromoethane (3.4 g; 18.9 mmol) were dissolved in 1,2-dichloroethane (15 mL). To this solution, aqueous NaOH (20% by weight; 10 mL) was added and the biphasic mixture was vigorously stirred under reflux for 6 hours until the originally yellow mixture turned pale yellow. The organic phase was filtered through a silica column which was then washed with CH2Cl2 /AcOEt (5:3 by volume) until the yellow band was about to come out. The combined organic solutions were evaporated to give a colorless oily residue. The oil was mixed with CH2Cl2 (2 mL) and ether (5 mL), and then treated with pentane (10 mL) and left for 1.5 hours. More pentane (50 ml) was added, and in 2 hours the fluffy white needles of dpppO were separated and dried under vacuum. The yield was 3.80 g (73%). 1H NMR (CDCl3, 20° C.), δ: 1.8 (m, 2H, CH2); 2.2 (m, 2H, CH2); 2.4 (m, 2H, CH2); 7.2-7.7 (m, 20H, Ph). 31P NMR (CDCl3, 20° C.), δ: -17.2 (s, 1P, PPh2); 32.0 (s, 1P, P(O)Ph2).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS05919984
Source datasetuspto-grants-1999_07
ORD IDord-8f6af12a08ad46deb152294c38c5d79b
Source noteuspto-grants-1999_07