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HRID58305

反应详情

EQUATION

反应方程式

HRID 58305 的结构方程式

REACTANTS

反应物

2
结构：OB(O)c1cccc(F)c1
HCID2733986

3-Fluorophenylboronic acid

C6H6BFO2

结构：CC(N=[N+]=[N-])c1nc2scc(C(F)(F)F)n2c(=O)c1Br
HCID86650085

未命名化合物

PRODUCTS

生成物

1
结构：CC(N=[N+]=[N-])c1nc2scc(C(F)(F)F)n2c(=O)c1-c1cccc(F)c1
HCID86650084

未命名化合物

收率 29%

PROCEDURE

实验过程

The desired compound was prepared according to the procedure of Example 8, step 5, using 7-(1-azidoethyl)-6-bromo-3-(trifluoromethyl)-5H-[1,3]thiazolo[3,2-a]pyrimidin-5-one and (3-fluorophenyl)boronic acid as the starting materials in 29% yield. LCMS for C15H10F4N5OS (M+H)+: m/z=383.9.