Water → HCID 22345598, compound

Participants

Reaction Steps

182 mg (4.8 mmol) of lithium aluminum hydride are placed in 20 ml of dry THF in a round-bottomed flask and under nitrogen. At 0° C., a solution of 640 mg (1.2 mmol) of dimethyl 4-{2-[4′-(2-ethyl[1,3]dioxolan-2-yl)-6-methyl-2′-propylbiphenyl-3-yl]ethyl}phthalate in 5 ml of THF is added dropwise. The reaction medium is stirred for 1 hour at room temperature. 200 μl of water are then added very slowly, followed by addition of 200 μl of 15% sodium hydroxide solution and then 600 μl of water. The medium is filtered and the filtrate is evaporated to dryness. 640 mg (100%) of the expected product are obtained in the form of a colorless oil.

Provenance & Evidence