HRID584752

反应详情

EQUATION

反应方程式

HRID 584752 的结构方程式

PROCEDURE

实验过程

1,5-bis(4-methoxyphenyl)-3-(1,3-thiazol-4-ylmethoxy)-1H-1,2,4-triazole (132 mg, 49.7% yield) was prepared from 1,5-bis(4-methoxyphenyl)-1H-1,2,4-triazol-3-ol and 4-(chloromethyl)-1,3-thiazole hydrochloride by the similar manner described for Example 18.