HRID586274

反应详情

EQUATION

反应方程式

HRID 586274 的结构方程式

PROCEDURE

实验过程

This was prepared in 89% yield by a similar procedure to that described in Example 3, step f, except using 7-bromo-3-trifluoromethylimidazo[1,2-b][1,2,4]triazine and 2-(6-fluoro-2′-(methanesulfonyl)biphenyl-3-yl)-4,4,5,5-tetramethyl-[1,3,2]dioxaborolane instead of 7-bromo-3-(1-fluoro-1-methylethyl)imidazo[1,2-b][1,2,4]triazine and 3-[2-fluoro-5-(4,4,5,5-tetramethyl-[1,3,2]dioxaborolan-2-yl)phenyl]pyridine: 1H NMR (360 MHz, CDCl3) δ 2.93 (3H, s), 7.37 (1H, td, J 1.6, 7.5 Hz), 7.47 (1H, dd, J 1.2, 7.4 Hz), 7.69 (1H, td, J 1.5, 7.8 Hz), 7.75 (1H, td, J 1.5, 7.4 Hz), 8.17-8.21 (2H, m), 8.27 (1H, dd, J 1.4, 8.0 Hz), 8.61 (1H, s), 8.78 (1H, s); MS (ES+) m/z 437 [M+H]+. Anal. Found: C, 52.15; H, 2.85; N, 12.74%. Required for C19H12F4N4O2S: C, 52.29; H, 2.77; N, 12.84%.

WORKUP

后处理

  1. customThis was prepared in 89% yield by a similar procedure to