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HRID589729

反应详情

EQUATION

反应方程式

HRID 589729 的结构方程式

REACTANTS

反应物

2
结构：O=S(=O)(Cl)c1ccc(-c2nsc(Cl)n2)s1
HCID2735820

5-(5-chloro-1,2,4-thiadiazol-3-yl)thiophene-2-sulfonyl Chloride

C6H2Cl2N2O2S3

结构：Nc1cccc(-c2nnn[nH]2)c1
HCID178507542

未命名化合物

PRODUCTS

生成物

1
结构：O=S(=O)(Nc1cccc(-c2nnn[nH]2)c1)c1ccc(-c2nsc(Cl)n2)s1
HCID178527496

未命名化合物

收率 68.1%

PROCEDURE

实验过程

The product was prepared according to General Procedure 1, described in Example 1, starting with 5-(5-chloro-1,2,4-thiadiazol-3-yl)thiophene-2-sulfonyl chloride (16.6 mg, 0.055 mmol) and 5-(3-amino-phenyl)tetrazole (8 mg, 0.05 mmol) affording 14.5 mg (68%) of the title compound. MS (ESI+) calcd for C13H8ClN7O2S3 424.959012, found 424.959022.

WORKUP

后处理

  1. customThe product was prepared