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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 59103Generated: October 29, 2026

4-Methoxy-1-(2-methoxy-4-nitrophenyl)-1H-imidazole → 3-methoxy-4-(4-methoxy-1H-imidazol-1-yl)aniline

https://huagongshe.com/reaction/59103

Reaction equation

Participants

RoleNameHCIDCharge
Reactant4-Methoxy-1-(2-methoxy-4-nitrophenyl)-1H-imidazoleHCID 117824150—
CatalystPalladiumHCID 23938—
SolventEthanolHCID 702—
Product3-methoxy-4-(4-methoxy-1H-imidazol-1-yl)anilineHCID 117823841—

Reaction Steps

4-Methoxy-1-(2-methoxy-4-nitrophenyl)-1H-imidazole (0.62 g, 2.49 mmol) was dissolved in EtOH (20 mL). Palladium on carbon (10%, 0.106 g, 0.10 mmol) was added. The mixture was shaken for 2 hours under an atmosphere of hydrogen (g). The mixture was filtered, the filter was washed with warm EtOH. The filtrate was concentrated to give the title compound as an oil, 0.52 g (95%).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS09439904B2
Source datasetuspto-grants-2016_09
ORD IDord-7e1ffaefaab042fabfeff8bf0af068df
Source noteuspto-grants-2016_09