Sodium → HCID 53960514, compound

Participants

Reaction Steps

A solution of sodium methylate in methanol (prepared from 1.2 g (50 m-moles) of sodium in 50 ml of methanol) is added to 14.4 g (50 m-moles) of 2-chloro-4-(3-pentylamino)-5-nitro-6-isopropyl-pyrimidine in 100 ml of methanol and the mixture is stirred for 1 hour. The solvent is distilled off and the residue is suspended in water and extracted with ether. The ethereal extracts are dried over MgSO4 and evaporated to yield 14 g of 2-methoxy-4-(3-pentylamino)-5-nitro-6-isopropyl-pyrimidine as an oil (nD20 : 1.5412).

Provenance & Evidence