Nitric Acid → 4-tert-Butyl-2-methyl-6-nitro-phenol
Reaction equation
[C:1]([C:5]1[CH:10]=[CH:9][C:8]([OH:11])=[C:7]([CH3:12])[CH:6]=1)([CH3:4])([CH3:3])[CH3:2].[N+:13]([O-])([OH:15])=[O:14]>C(O)(=O)C>[C:1]([C:5]1[CH:10]=[C:9]([N+:13]([O-:15])=[O:14])[C:8]([OH:11])=[C:7]([CH3:12])[CH:6]=1)([CH3:4])([CH3:3])[CH3:2]Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
4-tert-Butyl-2-methyl-phenol (1.64 g, 10 mmol) was dissolved in 15 mL acetic acid, fuming nitric acid (0.47 mL, 10 mmol) was added and the resulting solution was stirred at rt overnight. The reaction mixture was then poured onto crushed ice, and extracted with chloroform. The organic phase was washed with water, and dried over sodium sulfate. Evaporation gave 2.02 g the nitration product as a red oil.
Workup
- additionThe reaction mixture was then poured
- customonto crushed ice
- extractionextracted with chloroform
- washThe organic phase was washed with water
- dry with materialdried over sodium sulfate
- customEvaporation
Sources & evidence
- ORD record
- ord-3466fad70d9e4cf2a60ec95cecf9a0d2
- Source dataset
- uspto-grants-2011_03
- Patent number
- US07897599B2
Reaction notes
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