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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 605982Generated: October 26, 2026

Methyl iodide → 5-Bromo-2-(4-methoxybenzyl)-3,3-dimethylisoindolin-1-one

https://huagongshe.com/reaction/605982

Reaction equation

Participants

RoleNameHCIDCharge
ReactantMethyl iodideHCID 6328—
ReactantTetrahydrofuranHCID 8028—
ReactantSodium hydrideHCID 24758—
ReactantAmmonium ChlorideHCID 25517—
ReactantIodide IonHCID 30165—
Reactant4-Methoxybenzyl bromideHCID 165021—
Reactant5-bromo-2,3-dihydro-1H-isoindol-1-oneHCID 22607119—
SolventDimethylformamideHCID 6228—
SolventEthyl AcetateHCID 8857—
Product5-Bromo-2-(4-methoxybenzyl)-3,3-dimethylisoindolin-1-oneHCID 57589951—

Reaction Steps

A suspension of sodium hydride (130 mg, 60% dispersion in mineral oil, 3.2 mmol) and tetra-nbutylammonium iodide (243 mg, 0.68 mmol) in THF (20 mL) is stirred at rt and a solution of 5-bromo-2,3-dihydroisoindol-1-one (675 mg, 3.2 mmol) in THF (20 mL) and DMF (4 mL) is added. After 75 min 4-methoxybenzyl bromide (460 μL, 3.2 mmol) is added and stirring is continued for 4 h. Sodium hydride (635 mg, 60% dispersion in mineral oil, 15.9 mmol) is then added and stirring is continued for 30 min before iodomethane (1.19 mL, 19 mmol) is added and the mixture heated to 70° C. for 30 min. After cooling, NH4Cl (sat. aq.) is added and the mixture is diluted with ethyl acetate (120 mL). The layers are separated, the organic phase is dried over MgSO4 and the solvents removed under reduced pressure. The residue is purified by silica chromatography, eluting with 5% to 10% ethyl acetate in petroleum ether to afford the title compound as a yellow oil (640 mg, 1.78 mmol).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS07915256B2
Source datasetuspto-grants-2011_03
ORD IDord-11b18b600d6643afacfeaa39dae22cc8
Source noteuspto-grants-2011_03