Water → 3-(4-Fluorophenyl)-6-methylpicolinic acid
Reaction equation
[F:1][C:2]1[CH:7]=[CH:6][C:5]([C:8]2[C:9]([C:15]#N)=[N:10][C:11]([CH3:14])=[CH:12][CH:13]=2)=[CH:4][CH:3]=1.[OH-:17].[Na+].[OH2:19]>CO>[F:1][C:2]1[CH:7]=[CH:6][C:5]([C:8]2[C:9]([C:15]([OH:19])=[O:17])=[N:10][C:11]([CH3:14])=[CH:12][CH:13]=2)=[CH:4][CH:3]=1Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Conditions
- Temperature
- 100 °C
Procedure
To the solution of 3-(4-fluorophenyl)-6-methylpicolinonitrile (0.555 g, 2.615 mmol) in MeOH (3 mL) was added NaOH (1.1 g, 27.5 mmol) and H2O (1.8 mL). The mixture was heated at 100° C. for 8 h. The reaction was cooled to rt and acidified to pH-5. The solvent was removed in vacuo. The crude was extracted with MeOH. The solvent was removed in vacuo and the obtained acid was dried in vacuum for next step with no further purification. ESI-MS (m/z): 233 [M+1]+.
Workup
- temperatureThe reaction was cooled to rt
- customThe solvent was removed in vacuo
- extractionThe crude was extracted with MeOH
- customThe solvent was removed in vacuo
- customthe obtained acid was dried in vacuum for next step with no further purification
Sources & evidence
- ORD record
- ord-db06a1b42d6e4a128ca34831ff6e42a1
- Source dataset
- uspto-grants-2016_09
- Patent number
- US09440982B2
Reaction notes
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