Water → 3-(4-Fluorophenyl)-6-methylpicolinic acid

HRID 61004Notes

Reaction equation

HRID 61004 reaction equation
[F:1][C:2]1[CH:7]=[CH:6][C:5]([C:8]2[C:9]([C:15]#N)=[N:10][C:11]([CH3:14])=[CH:12][CH:13]=2)=[CH:4][CH:3]=1.[OH-:17].[Na+].[OH2:19]>CO>[F:1][C:2]1[CH:7]=[CH:6][C:5]([C:8]2[C:9]([C:15]([OH:19])=[O:17])=[N:10][C:11]([CH3:14])=[CH:12][CH:13]=2)=[CH:4][CH:3]=1

Participants

5

Conditions

Temperature
100 °C

Procedure

To the solution of 3-(4-fluorophenyl)-6-methylpicolinonitrile (0.555 g, 2.615 mmol) in MeOH (3 mL) was added NaOH (1.1 g, 27.5 mmol) and H2O (1.8 mL). The mixture was heated at 100° C. for 8 h. The reaction was cooled to rt and acidified to pH-5. The solvent was removed in vacuo. The crude was extracted with MeOH. The solvent was removed in vacuo and the obtained acid was dried in vacuum for next step with no further purification. ESI-MS (m/z): 233 [M+1]+.

Workup

  1. temperatureThe reaction was cooled to rt
  2. customThe solvent was removed in vacuo
  3. extractionThe crude was extracted with MeOH
  4. customThe solvent was removed in vacuo
  5. customthe obtained acid was dried in vacuum for next step with no further purification

Sources & evidence

ORD record
ord-db06a1b42d6e4a128ca34831ff6e42a1
Source dataset
uspto-grants-2016_09
Patent number
US09440982B2

Reaction notes

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