Fluorotelomer alcohol 10:2 → HCID 19598604, compound

HRID 611957Notes

Reaction equation

HRID 611957 reaction equation
[F:1][C:2]([F:34])([CH2:31][CH2:32][OH:33])[C:3]([F:30])([F:29])[C:4]([F:28])([F:27])[C:5]([F:26])([F:25])[C:6]([F:24])([F:23])[C:7]([F:22])([F:21])[C:8]([F:20])([F:19])[C:9]([F:18])([F:17])[C:10]([F:16])([F:15])[C:11]([F:14])([F:13])[F:12]>[Pd]>[CH2:11]([O:33][CH2:32][CH2:31][C:2]([F:34])([F:1])[C:3]([F:29])([F:30])[C:4]([F:27])([F:28])[C:5]([F:25])([F:26])[C:6]([F:24])([F:23])[C:7]([F:21])([F:22])[C:8]([F:20])([F:19])[C:9]([F:18])([F:17])[C:10]([F:16])([F:15])[C:11]([F:14])([F:13])[F:12])[CH2:10][CH2:9][CH2:8][CH2:7][CH2:6][CH2:5][CH2:4][CH2:3][CH2:2][CH2:31][CH3:32]

Participants

3

Reactant 1

HCID 70083Fluorotelomer alcohol 10:2

Product 1

HCID 19598604HCID 19598604, compoundYield 193.3%

Reagents, catalysts & solvents 1

HCID 23938PalladiumCatalyst

Procedure

In the same manner as in Example 1, except that 2-(perfluorodecyl)ethanol 16.9 g (0.03 mol) was used instead of 2-(perfluorooctyl)ethanol and the amount of 5% Pd-C (pH 6.8) to be added was 0.34 g, reaction was carried out to obtain the objective dodecyl{2-(perfluorodecyl)ethyl}ether 21.1 g (0.029 mol) as a white solid. Isolation yield was 96%.

Workup

  1. custom0.34 g, reaction

Sources & evidence

ORD record
ord-93a7a4289ff540e195b687733b10458e
Source dataset
uspto-grants-1999_12
Patent number
US06002048

Reaction notes

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