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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 61311Generated: October 26, 2026

Potassium Hydroxide → JWH 250 N-pentanoic acid metabolite

https://huagongshe.com/reaction/61311

Reaction equation

Participants

RoleNameHCIDCharge
ReactantPotassium HydroxideHCID 14797—
ReactantEthyl 5-(3-(2-(2-methoxyphenyl)acetyl)-1H-indol-1-yl)pentanoateHCID 86691093—
SolventWaterHCID 962—
ProductJWH 250 N-pentanoic acid metaboliteHCID 8669109271%

Reaction Steps

Ethyl 5-(3-(2-(2-methoxyphenyl)acetyl)-1H-indol-1-yl)pentanoate [Ethyl N-(carboxybutyrate) JWH-250] 7 (856 mg, 2.18 mmol) was dissolved in tertahydrofuran (15 ml) and water (15 ml) was added followed by potassium hydroxide (287 mg, 4.36 mmol). The reaction mixture was stirred at room temperature overnight. The solvent was removed in vacuo, the residue was acidified to pH 3 and extracted three times with ethyl acetate (3×50 ml). The organic fractions were combined, dried over sodium sulphate and concentrated under vacuo. The residue was purified by column chromatography (silica gel, 50%-100% ethyl acetate in hexane) and then recrystalised from ethylacetate/hexane to give 565 mg (71%) 5-(3-(2-(2-methoxyphenyl)acetyl)-1H-indol-1-yl)pentanoic acid [N-(carboxybutyric acid) JWH-250] (Hapten 2) as a white solid.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS09441033B2
Source datasetuspto-grants-2016_09
ORD IDord-a7e6ed454f594540b59bfe29c1ded721
Source noteuspto-grants-2016_09