HRID617164
反应详情
EQUATION
反应方程式
REACTANTS
反应物
PRODUCTS
生成物
PROCEDURE
实验过程
The same procedure as in Example 48 was repeated, using 3.90 g (7.13 mmol) of Compound 47 obtained in Example 47, except that ethyl bromoacetate was used in place of methyl iodide, to give 2.81 g (yield: 62%) of Compound 54 as white crystals.