HRID617164

反应详情

EQUATION

反应方程式

HRID 617164 的结构方程式

PROCEDURE

实验过程

The same procedure as in Example 48 was repeated, using 3.90 g (7.13 mmol) of Compound 47 obtained in Example 47, except that ethyl bromoacetate was used in place of methyl iodide, to give 2.81 g (yield: 62%) of Compound 54 as white crystals.