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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 620142Generated: October 30, 2026

Formaldehyde → HCID 23044711, compound

https://huagongshe.com/reaction/620142

Reaction equation

Participants

RoleNameHCIDCharge
ReactantFormaldehydeHCID 712—
ReactantDiethylamineHCID 8021—
ReactantHCID 14957288HCID 14957288—
SolventMethanolHCID 887—
ProductHCID 23044711HCID 2304471174.4%

Reaction Steps

56.81 g (44.0 mmol) of tetra-n-heptyl methylenebisphosphonate, 6.61 g (220.0 mmol) of paraformaldehyde and 3.22 g (64.0 mmol) of diethylamine are combined with the same reactants and the same conditions as described above in Example I. This mixture is then refluxed for 48 hours. After the methanol is eliminated as described above in Example I, about 19 g of tetra-n-heptyl ethenylidenebisphosphonate is produced as a clear liquid.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS04820698
Source datasetuspto-grants-1989_04
ORD IDord-cc161c96a62e4345898e461877af6bea
Source noteuspto-grants-1989_04