HRID620150

反应详情

EQUATION

反应方程式

HRID 620150 的结构方程式

AUXILIARIES

试剂、催化剂与溶剂

1

PROCEDURE

实验过程

This compound was prepared in 89% yield from the ester 4d (11.2 g, 40 mmol) by reduction with lithium borohydride in dry DME analogous to the method described earlier1,2. TLC Rf 0.50 (eluent MeOH/CHCl3, 7/93). 1H NMR (CDCl3) δ 1.40 (s, 9H, t-Bu), 2.00-2.53 (m, 1H, OH), 2,83 (d, J=5.4 Hz, 2H, CH2Ph), 3.33-4.08 (m, 3H, CH2OH, CHCH2), 4.48-4.94 (br d, 1H, NH), 7.22 (s, 5H, Ph). CI MS, m/e 252 (M+ +1).