Zirconium sulfate tetrahydrate → Zirconium
Reaction equation
O.O.O.O.[S:5]([O-:9])([O-:8])(=[O:7])=[O:6].[Zr+4:10].[S:11]([O-:15])([O-:14])(=[O:13])=[O:12]>O>[S:5]([O-:9])([O-:8])(=[O:7])=[O:6].[Zr+4:10].[S:11]([O-:15])([O-:14])(=[O:13])=[O:12].[Zr:10]Participants
4
Reactant 1
Product 2
Reagents, catalysts & solvents 1
Procedure
A zirconium sulfate solution was prepared by dissolving commercial zirconium sulfate tetrahydrate in distilled water. Analysis of the solution gave a zirconium content of 195 grams per liter (expressed as ZrO2) and a sulfate content of 338 grams per liter (expressed as SO4).
Sources & evidence
- ORD record
- ord-3e203682003e413e942e1b4c25a16f72
- Source dataset
- uspto-grants-1989_04
- Patent number
- US04822575
Reaction notes
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