2H-Azepin-2-one, hexahydro-1-(hydroxymethyl)- → Formaldehyde

Participants

Reaction Steps

It has already been disclosed that N-methylolcaprolactam can be prepared in a yield of 67% of the theoretical yield from caprolactam and excess paraformaldehyde (50% excess) in 95% strength ethanol in the presence of 4.2 mol % of sodium hydroxide as catalyst (J. Am. Chem. Soc. 70 (1948), 2115-2118). The reaction specified is carried out in approximately 50% strength solution.

Provenance & Evidence