HRID62962

反应详情

EQUATION

反应方程式

HRID 62962 的结构方程式

PROCEDURE

实验过程

2-Chloromethyl-6-cyclopentylsulfanyl-pyridine (0.040 g, 0.17 mmol) obtained in Step C of Preparation Example 27 and 2-(3-fluoro-4-hydroxy-phenyl)-cyclopropane carboxylic acid ethyl ester (0.040 g, 0.17 mmol) obtained in Step C of Preparation Example 44 were used to react sequentially in the same manner as in Steps A and B of Example 1 to obtain the title compound (0.061 g, 89%).

WORKUP

后处理

  1. customto react sequentially in the same manner as in Steps A and B of Example 1