HRID62972

反应详情

EQUATION

反应方程式

HRID 62972 的结构方程式

PROCEDURE

实验过程

3-Chloromethyl-2-isopropylsulfanyl-pyridine (33 mg, 0.16 mmol) obtained in Step C of Preparation Example 1 and 2-(3-chloro-4-hydroxy-phenyl)-cyclopropane carboxylic acid ethyl ester (43 mg, 0.17 mmol) obtained in Step B of Preparation Example 47 were used to react sequentially in the same manner as in Steps A and B of Example 1 to obtain the title compound (42 mg, 80%).

WORKUP

后处理

  1. customto react sequentially in the same manner as in Steps A and B of Example 1