HRID62990

反应详情

EQUATION

反应方程式

HRID 62990 的结构方程式

PROCEDURE

实验过程

3-Chloromethyl-2-propylsulfanyl-pyridine (0.016 g, 0.08 mmol) obtained in Step C of Preparation Example 14 and 2-(3-fluoro-4-hydroxy-phenyl)-cyclopropane carboxylic acid methyl ester (less polar) (0.017 g, 0.08 mmol) obtained in Step C of Preparation Example 64 were used to react sequentially in the same manner as in Steps A and B of Example 1 to obtain the title compound (0.014 g, 48%).

WORKUP

后处理

  1. customobtained in Step C of Preparation Example 64
  2. customto react sequentially in the same manner as in Steps A and B of Example 1