HRID62991

反应详情

EQUATION

反应方程式

HRID 62991 的结构方程式

PROCEDURE

实验过程

2-Chloromethyl-6-cyclopentylsulfanyl-pyridine (0.026 g, 0.11 mmol) obtained in Step C of Preparation Example 27 and [2-(3-fluoro-4-hydroxy-phenyl)-cyclopropyl]-acetic acid methyl ester (0.026 g, 0.11 mmol) obtained in Step F of Preparation Example 53 were used to react sequentially in the same manner as in Steps A and B of Example 1 to obtain the title compound (0.040 g, 87%).

WORKUP

后处理

  1. customto react sequentially in the same manner as in Steps A and B of Example 1