HRID62992

反应详情

EQUATION

反应方程式

HRID 62992 的结构方程式

PROCEDURE

实验过程

3-Chloromethyl-2-propylsulfanyl-pyridine (0.024 g, 0.12 mmol) obtained in Step C of Preparation Example 14 and [2-(3-fluoro-4-hydroxy-phenyl)-cyclopropyl]-acetic acid methyl ester (0.027 g, 0.12 mmol) obtained in Step F of Preparation Example 53 were used to react sequentially in the same manner as in Steps A and B of Example 1 to obtain the title compound (0.043 g, 96%).

WORKUP

后处理

  1. customto react sequentially in the same manner as in Steps A and B of Example 1