HRID62995

反应详情

EQUATION

反应方程式

HRID 62995 的结构方程式

PROCEDURE

实验过程

3-Chloromethyl-2-cyclopropylmethylsulfanyl-pyridine (0.026 g, 0.12 mmol) obtained in Step C of Preparation Example 18 and 2-(3-fluoro-4-hydroxy-phenyl)-cyclopropane carboxylic acid methyl ester (less polar) (0.025 g, 0.12 mmol) obtained in Step C of Preparation Example 64 were used to react sequentially in the same manner as in Steps A and B of Example 1 to obtain the title compound (0.042 g, 95%).

WORKUP

后处理

  1. customobtained in Step C of Preparation Example 64
  2. customto react sequentially in the same manner as in Steps A and B of Example 1