HRID636541

反应详情

EQUATION

反应方程式

HRID 636541 的结构方程式

AUXILIARIES

试剂、催化剂与溶剂

2

PROCEDURE

实验过程

1.6 g (3.8 mmol) of the compound from Example V are dissolved in 350 ml of CH2Cl2 and treated with 7.5 g of MnO2. The mixture is kept under reflux for 2 h, solid is filtered off with suction through Celite and the filtrate is concentrated. The residue crystallizes from ether/petroleum ether. 1.1 g (69% of theory) of the title compound are obtained.

WORKUP

后处理

  1. temperatureunder reflux for 2 h
  2. filtrationsolid is filtered off with suction through Celite
  3. concentrationthe filtrate is concentrated
  4. customThe residue crystallizes from ether/petroleum ether