Pentachlorophenol → 2,4,6-Trichlorophenol
Reaction equation
C1(O)C=CC=CC=1.[Cl:8][C:9]1[C:14]([OH:15])=[C:13]([Cl:16])[C:12](Cl)=[C:11]([Cl:18])[C:10]=1Cl>>[Cl:8][C:9]1[CH:10]=[C:11]([Cl:18])[CH:12]=[C:13]([Cl:16])[C:14]=1[OH:15]Participants
3
Reactant 2
Product 1
Procedure
About 143 g of phenol (an amount that should lead to an equivalent amount of pentachlorophenol product, by moles, obtained when about 300 g of 2,4,6-trichlorophenol is used) were added to a reactor at 60° C. with 0.75 g of AlCl3 (about 0.25 wt. % based on trichlorophenol). The same stirring rate (100-120 RPM) and chlorine flow rate (1.5 mol/hr) as experiments that started with trichlorophenol were used.
Sources & evidence
- ORD record
- ord-19c7e134b41b4f07a312b3ad2b48819b
- Source dataset
- uspto-grants-2010_04
- Patent number
- US07696389B2
Reaction notes
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