2,6-Lutidine → 2-(3-Methoxyphenyl)oxazol-4-yl trifluoromethanesulfonate

Participants

Reaction Steps

Compound 16 (516 mg, 1 eq) was dissolved in CH2Cl2. To the resulting solution, at 0° C., was added 501 μL (1.6 eq) of 2,6-lutidine, followed by the dropwise addition of Tf2O (681 ml, 1.5 eq). The resulting mixture was stirred for 4 h at RT, then an additional 501 μL (1.6 eq) of 2,6-lutidine and 681 ml (1.5 eq) of Tf2O were added. After 1 h, the mixture was evaporated and the residue purified by flash chromatography (SiO2, CH2Cl2/hexane, 9/1) giving 17 as a red oil in 75% yield.

Provenance & Evidence