Diethyl Ether → HCID 54509558, compound

HRID 647378Notes

Reaction equation

HRID 647378 reaction equation
[H-].[Al+3].[Li+].[H-].[H-].[H-].CCOCC.[Cl:12][C:13]1[CH:37]=[C:36]([C:38]([F:41])([F:40])[F:39])[CH:35]=[CH:34][C:14]=1[O:15][C:16]1[CH:33]=[CH:32][C:19]([O:20][CH:21]([CH3:31])[C:22]([O:29][CH3:30])=[CH:23][C:24](OCC)=[O:25])=[CH:18][CH:17]=1>O>[Cl:12][C:13]1[CH:37]=[C:36]([C:38]([F:39])([F:41])[F:40])[CH:35]=[CH:34][C:14]=1[O:15][C:16]1[CH:33]=[CH:32][C:19]([O:20][CH:21]([CH3:31])[C:22]([O:29][CH3:30])=[CH:23][CH2:24][OH:25])=[CH:18][CH:17]=1

Participants

5

Reactant 3

HCID 3283Diethyl Ether3×HCID 21226445Aluminium lithium hydrideHCID 53893716HCID 53893716, compound

Product 1

HCID 54509558HCID 54509558, compound

Reagents, catalysts & solvents 1

HCID 962WaterSolvent

Procedure

To a mixture of lithium aluminum hydride (200 mg) and anhydrous ether (5 ml.) is added dropwise at 0°, a mixture of ethyl 4[4-(2-chloro-4-trifluoromethylphenoxy)phenoxy]-3-methoxy-2-pentenoate (400 mg) and ether (5 ml.). After addition is complete, the mixture is stirred for about minutes. Wet ether and water is added to destroy excess hydride. Filtration and evaporation of filtrate gives 4-[4-(2-chloro-4-trifluoromethylphenoxy)phenoxy]-3-methoxy-2-penten-1-ol.

Workup

  1. additionis added dropwise at 0°
  2. additionAfter addition
  3. customto destroy excess hydride
  4. filtrationFiltration and evaporation of filtrate

Sources & evidence

ORD record
ord-b97660b75724474ca3d5782bb5765a04
Source dataset
uspto-grants-1983_10
Patent number
US04408076

Reaction notes

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