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HRID647379

反应详情

EQUATION

反应方程式

HRID 647379 的结构方程式

REACTANTS

反应物

2
结构：O=S(Cl)Cl
HCID24386

Thionyl chloride

Cl2OS

结构：COC(=CC(=O)O)C(C)Oc1ccc(Oc2ccc(C(F)(F)F)cc2Cl)cc1
HCID53860348

未命名化合物

PRODUCTS

生成物

1
结构：COC(=CC(=O)Cl)C(C)Oc1ccc(Oc2ccc(C(F)(F)F)cc2Cl)cc1
HCID57096965

未命名化合物

AUXILIARIES

试剂、催化剂与溶剂

1
结构：CCOCC
溶剂HCID3283

Diethyl Ether

C4H10O

PROCEDURE

实验过程

Thionyl chloride (20 ml.) is added to 4-[4-(2-chloro-4-trifluoromethylphenoxy)phenoxy]-3-methoxy-2-pentenoic acid (10 mm.) in anhydrous ether (10 ml.). The mixture is refluxed for a few hours. Then, ether and excess thionyl chloride is removed by vacuum to yield 4-[4-(2-chloro-4-trifluoromethylphenoxy)phenoxy]-3-methoxy-2-pentenoyl chloride.

WORKUP

后处理

  1. temperatureThe mixture is refluxed for a few hours
  2. customThen, ether and excess thionyl chloride is removed by vacuum