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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 647384Generated: October 30, 2026

Water → 3-Methoxy-4-{4-[4-(trifluoromethyl)phenoxy]phenoxy}pent-2-en-1-ol

https://huagongshe.com/reaction/647384

Reaction equation

Participants

RoleNameHCIDCharge
ReactantWaterHCID 962—
ReactantHydrideHCID 166653—
ReactantAluminium lithium hydrideHCID 21226445—
ReactantHCID 53713180HCID 53713180—
SolventDiethyl EtherHCID 3283—
Product3-Methoxy-4-{4-[4-(trifluoromethyl)phenoxy]phenoxy}pent-2-en-1-olHCID 53757857—

Reaction Steps

To a slurry of LiAlH4 (400 mg) in anhydrous ether (20 ml) is added dropwise at 0°, a solution of ethyl 4-[4-(4-trifluoromethylphenoxy)phenoxy]-3-methoxy-2-pentenoate (1.2 g) in ether (10 ml). After addition is complete, the reaction mixture is stirred for about 10 minutes. Excess hydride is decomposed with wet ether and water. After filtration, the filtrate is concentrated to give the alcohol, 4-[4-(4-trifluoromethylphenoxy) phenoxy]-3-methoxy-2-penten-1-ol.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS04408076
Source datasetuspto-grants-1983_10
ORD IDord-be93f812b9224915a22b7be7dacda2ea
Source noteuspto-grants-1983_10