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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 64985Generated: October 26, 2026

Methyl iodide → 2-(4-Methoxyphenyl)propanenitrile

https://huagongshe.com/reaction/64985

Reaction equation

Participants

RoleNameHCIDCharge
ReactantMethyl iodideHCID 6328—
ReactantAmmonium ChlorideHCID 25517—
ReactantBenzeneacetonitrile, 4-methoxy-HCID 66031—
ReactantButyllithiumHCID 178418339—
SolventTetrahydrofuranHCID 8028—
Product2-(4-Methoxyphenyl)propanenitrileHCID 1229767093.1%

Reaction Conditions

Temperature-78 °C

Reaction Steps

14.7 g (0.10 mole) of p-methoxyphenylacetonitrile was dissolved in 250 ml of dry tetrahydrofuran and placed in a dry ice/isopropanol bath under N2. 69.0 ml of 1.6M n-butyl lithium (0.11 mole) was added dropwise over 30 minutes and the mixture stirred at -78° C. for one hour. The lithium salt of the nitrile precipitated as a yellow solid during this time. 71.0 g (0.50 mole) of methyl iodide was then added and stirring at -78° C. continued for an additional hour. The mixture was then poured into saturated ammonium chloride and the product extracted into diethyl ether, washed with saturated sodium chloride and dried over sodium sulfide. It was filtered and evaporated, redissolved in methylene chloride and passed through Florisel®. Evaporation gave 15.0 g of α-(p-methoxyphenyl)propionitrile as an orange oil.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS04611078
Source datasetuspto-grants-1986_09
ORD IDord-c77584732c344998aff750ca8df02bbf
Source noteuspto-grants-1986_09