Back
HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 650996Generated: October 31, 2026

Triphenylphosphine → 2-(4'-Fluorophenyl)-4-[4'-(3-dimethylamino-2-propyn-1-yl)phenyl]thiazole

https://huagongshe.com/reaction/650996

Reaction equation

Participants

RoleNameHCIDCharge
ReactantTriphenylphosphineHCID 11776—
ReactantN,N-DimethylpropargylamineHCID 81643—
Reactant4-(4-Bromo-phenyl)-2-(4-fluoro-phenyl)-thiazoleHCID 11174998—
CatalystPalladium ChlorideHCID 24290—
CatalystCopper(1+) iodide; Copper(I) iodide; Cuprous iodide; Cuprous iodide (CuI)HCID 24350—
SolventAcetonitrileHCID 6342—
SolventDiethylamineHCID 8021—
Product2-(4'-Fluorophenyl)-4-[4'-(3-dimethylamino-2-propyn-1-yl)phenyl]thiazoleHCID 22611058—

Reaction Steps

In a 100 ml flask is placed triphenylphosphine (80 mg, 10%), PdCl2 (40 mg, 5%) and 2-(4′-fluorophenyl)-4-(4′-bromophenyl)thiazole (0.98 g, 2.9 mmol) in 20 mL of diethylamine. After stirring for 15 min under N2 atmosphere, CuI (30 mg, 5%) and 1-dimethylamino-2-propyne (0.27 g, 3.18 mmol) in 20 ml of acetonitrile are added to the mixture. After 18 h of heating, the solvent is evaporated under reduced pressure and the residue is filtered through silica gel pad (50 g) using CHCl3 (400 mL) and 2% MeOH in CHCl3(400 mL). A large portion of unreacted 2-(4′-fluorophenyl)-4-(4′-bromophenyl)thiazole is recovered after removal of chloroform filtrate (0.55 g, 56%). The second part of the filtrate (2% MeOH in CHCl3) is concentrated and the residual solid is then purified over silica gel column eluting with 2% MeOH in CHCl3. 2-(4′-fluorophenyl)-4-[4′-(3-dimethylamino-2-propyn-1-yl)phenyl]thiazole is obtained after concentration and trituration with hexane (0.25 g, 27% yield), mp. 98-9° C.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS06277873B1
Source datasetuspto-grants-2001_08
ORD IDord-0b6c614c60de42b8b3beef40aff981ea
Source noteuspto-grants-2001_08